Learning Outcomes
- Compute basic derivatives using algebraic rules.
Section 10.3 Elementary Derivative Rules (DF3)
Subsection 10.3.1 Activities
Observation 10.41.
We know how to find the derivative function using the limit definition of the derivative. From the activities in the previous section, we have seen that this process gets cumbersome when the functions are more complicated. In this section we will discuss shortcuts to calculate derivatives, known as “differentiation rules”.
Activity 10.42.
In this activity we will try to deduce a rule for finding the derivative of a power function. Note, a power function is a function of the form \(f(x) = x^{n}\) where \(n\) is any real number.
(a)
Using the limit definition of the derivative, what is \(f'(x)\) for the power function \(f(x) = x\text{?}\)
- -1
- 1
- 0
- Does not exist
Answer.
B: 1
(b)
Using the limit definition of the derivative, what is \(f'(x)\) for the power function \(f(x) = x^{2}\text{?}\)
- 0
- \(\displaystyle -2x\)
- \(\displaystyle 2x\)
- \(\displaystyle 2x+1\)
Answer.
C: \(2x\)
(c)
Using the limit definition of the derivative, what is \(f'(x)\) for the power function \(f(x) = x^{3}\text{?}\)
- \(\displaystyle 3x^2\)
- \(\displaystyle -3x^2\)
- \(\displaystyle 3x^2-3x\)
- \(\displaystyle -3x^2+3x\)
Answer.
A: \(3x^2\)
(d)
WITHOUT using the limit definition of the derivative, what is your best guess for \(f'(x)\) when \(f(x) = x^{4}\text{?}\) (See if you can find a pattern from the first three tasks of this activity.)
- \(\displaystyle 3x^2\)
- \(\displaystyle 3x^3\)
- \(\displaystyle 4x^2\)
- \(\displaystyle 4x^3\)
Answer.
D: \(4x^3\)
Theorem 10.43. The Power Rule.
The derivative of the power function\(f(x) = x^n\text{,}\) for any real number \(n\text{,}\) is
\begin{equation*}
f'(x) = n \, x^{n-1}.
\end{equation*}
Observation 10.44.
We have been using \(f'(x)\text{,}\) read “\(f\) prime”, to denote a derivative of the function \(f(x)\text{.}\) There are other ways to denote the derivative of \(y=f(x)\text{:}\) \(y'\) or \(\dfrac{df}{dx}\text{,}\) pronounced “dee-f dee-x”. If you want to take the derivative of \(f'(x)\text{,}\) \(y'\text{,}\) or \(\dfrac{df}{dx}\) to get the second derivative of \(f(x)\text{,}\) the notation is \(f''(x)\text{,}\) \(y''\text{,}\) or \(\dfrac{d^2f}{dx^2}\text{.}\)
Activity 10.45.
Using Theorem 10.43, which of the following statement(s) are true? For those statements that are wrong, give the correct derivative.
- The derivative of \(y = x^{10}\) is \(y' = 10x^{11}.\)
- The derivative of \(y = x^{-8}\) is \(y' = -8x^{-9}.\)
- The derivative of \(y = x^{100}\) is \(y' = 100x^{99}.\)
- The derivative of \(y = x^{-17}\) is \(y' = -17x^{-16}.\)
Answer.
The statements B and C are true.
A should be \(y' = 10x^9\) and D should be \(-17x^{-18}\text{.}\)
Theorem 10.46. The Derivative of a Constant Function.
If \(f(x) = c\text{,}\) for some constant real number \(c\text{,}\) then \(f'(x) = 0\text{.}\)
Activity 10.47.
Using Theorem 10.46, which of the following statement(s) are true? Note: Pay attention to the independent variable (the input) of the function.
- The derivative of \(y(x) = 10\) is \(y'(x) = 9\text{.}\)
- The derivative of \(y(t) = x\) is \(y'(t) = 0\text{.}\)
- The derivative of \(y(a) = x^2\) is \(y'(a) = 2x\text{.}\)
- The derivative of \(y(x) = -5\) is \(y'(x) = -4\text{.}\)
Answer.
Only B is true.
Theorem 10.48. The Scalar Multiple Rule.
If \(c\) is a real number and \(f(x)\) is a differentiable function, then using the Scalar Multiple Law for limits, we have that
\begin{equation*}
\frac{d}{dx}\left[cf(x)\right] = c\frac{d}{dx}\left[f(x)\right]
\end{equation*}
Activity 10.49.
What is the derivative of the function \(y(x) = 12x^{2/3}\text{?}\)
- \(\displaystyle y'(x) = 8x^{5/3}.\)
- \(\displaystyle y'(x) = 18x^{-1/3}.\)
- \(\displaystyle y'(x) = 8x^{-1/3}.\)
- \(\displaystyle y'(x) = 18x^{5/3}.\)
Answer.
C: \(y'(x) = 8x^{-1/3}.\)
Theorem 10.50. The Sum/Difference Rule.
If \(f(x)\) and \(g(x)\) are both differentiable, then using the Sum/Differences Law for limits, we have that
\begin{equation*}
\frac{d}{dx}\left[f(x) \pm g(x)\right] = \frac{d}{dx}\left[f(x)\right]\pm\frac{d}{dx}\left[g(x)\right]
\end{equation*}
Activity 10.51.
What are the first and second derivatives for the arbitrary quadratic function given by \(f(x) = ax^2 + bx + c\text{,}\) where \(a,\,b,\,c\) are any real numbers?
- \(\displaystyle f'(x) = 2ax + bx + c, \, f''(x)=2a +b.\)
- \(\displaystyle f'(x) = 2x + 1, \, f''(x)=2.\)
- \(\displaystyle f'(x) = 2ax + b , \, f''(x)=2a.\)
- \(\displaystyle f'(x) = ax + b, \, f''(x)=a.\)
Answer.
C: \(f'(x) = 2ax + b , \, f''(x)=2a.\)
Activity 10.52.
We can look at power functions with fractional exponents like \(f(x)= x^{\frac{1}{4}}=\sqrt[4]{x}\) or with negative exponents like \(g(x)= x^{-4} = \dfrac{1}{x^4}\text{.}\) What is the derivative of these two functions?
- \(\displaystyle f'(x) = \frac{1}{4 \sqrt[4]{x^3}}, \, g'(x) = \frac{-4}{x^3}.\)
- \(\displaystyle f'(x) = \frac{1}{4} \sqrt[4]{x^3}, \, g'(x) = \frac{-4}{x^5}.\)
- \(\displaystyle f'(x) = \frac{1}{4} \sqrt[4]{x^3}, \, g'(x) = \frac{-4}{x^3}.\)
- \(\displaystyle f'(x) = \frac{1}{4 \sqrt[4]{x^3}}, \, g'(x) = \frac{-4}{x^5}.\)
Answer.
D: \(f'(x) = \frac{1}{4 \sqrt[4]{x^3}}, \, g'(x) = \frac{-4}{x^5}.\)
Theorem 10.53. The Derivative of an Exponential Function.
The derivative of the exponential function\(f(x) = b^x\text{,}\) for any positive number \(b\text{,}\) is
\begin{equation*}
f'(x) =\ln(b) \, b^x=\log(b)\,b^x=\log_e(b)b^x\text{.}
\end{equation*}
(In this book, we use both \(\ln\) and \(\log\) to denote the “natural logarithm” with base \(e\text{.}\) While \(\log\) is sometimes used to denote the “common logarithm” base \(10\text{,}\) we prefer to write \(\log_{10}\) in that case.)
Observation 10.54.
A special case of Theorem 10.53 is when \(b = e\text{,}\) where \(e\) is the base of the natural logarithm function. In this case let \(f(x) = e^x\text{.}\) Then
\begin{equation*}
f'(x) =\ln(e) \, e^{x} = e^{x}.
\end{equation*}
So \(f(x)=e^x\) is a special function for which \(f'(x)=f(x)\text{.}\)
Activity 10.55.
The first derivative of the function \(g(x) = x^e + e^{x}\) is given by \(g'(x) = ex^{e-1} + e^{x}\text{.}\) What is the second derivative of \(g(x)\text{?}\)
- \(\displaystyle g''(x) = x^{e} + e^{x}.\)
- \(\displaystyle g''(x) = e(e-1)x^{e-2} + e^x.\)
- \(\displaystyle g''(x) = ex^{e-1} + e^x.\)
- \(\displaystyle g''(x) = e^x.\)
Answer.
B: \(g''(x) = e(e-1)x^{e-2} + e^x.\)
Theorem 10.56. The Derivative of the Sine and Cosine Functions.
If \(f(x) = \sin(x)\text{,}\) then \(f'(x) = \cos(x)\text{.}\) If \(f(x) = \cos(x)\text{,}\) then \(f'(x) = -\sin(x)\text{.}\)
Activity 10.57.
The derivative of \(f(x) = 7\sin(x) + 2e^x + 3x^{1/3} - 2\) is,
- \(\displaystyle f'(x) = 7\cos(x) + 2e^{x} + x^{-2/3} - 2x.\)
- \(\displaystyle f'(x) = 7\cos(x) + 2e^{x} + -2x^{-2/3} - 2.\)
- \(\displaystyle f'(x) = -7\sin(x) + e^{x} + x^{-2/3}.\)
- \(\displaystyle f'(x) = -7\cos(x) + 2e^{x}\ln(x) + x^{-2/3}.\)
- \(\displaystyle f'(x) = 7\cos(x) + 2e^x + x^{-2/3}.\)
Answer.
E: \(f'(x) = 7\cos(x) + 2e^x + x^{-2/3}.\)
Theorem 10.58. The Derivative of the Natural Log Function.
If \(f(x) = \ln(x)\text{,}\) then
\begin{equation*}
f'(x) = \frac{1}{x}\text{.}
\end{equation*}
Activity 10.59.
Which of the following statements is NOT true?
- The derivative of \(y = 2\ln(x)\) is \(y' = \dfrac{2}{x}.\)
- The derivative of \(y = \dfrac{\ln(x)}{2}\) is \(y' = \dfrac{1}{2x}.\)
- The derivative of \(y = \dfrac{2}{3}\ln(x)\) is \(y' = \dfrac{3}{2x}.\)
- The derivative of \(y = \ln(x^{2})\) is \(y' = \dfrac{2}{x}\text{.}\)
Answer.
C: The derivative of \(y = \dfrac{2}{3}\ln(x)\) is \(y' = \dfrac{3}{2x}.\)
Activity 10.60.
Demonstrate and explain how to find the derivative of the following functions. Be sure to explicitly denote which derivative rules (scalar multiple, sum/difference, etc.) you are using in your work.
(a)
\begin{equation*}
g(x) = 2 \, \cos\left(x\right) - 3 \, e^x
\end{equation*}
Answer.
\(-2\sin(x) -3e^x\)
(b)
\begin{equation*}
h(w) = \sqrt[5]{w^7} + \frac{6}{w^{5}}
\end{equation*}
Answer.
\(\dfrac{7}{5}w^{2/5} -30w^{-6}=\dfrac{7\sqrt[5]{w^2}}{5}-\dfrac{30}{w^6}\)
(c)
\begin{equation*}
f(t) = -4 \, t^{5} + 5 \, t^{3} + t - 8
\end{equation*}
Answer.
\(-20t^4 + 15t^2 + 1\)
Activity 10.61.
Suppose that the temperature (in degrees Fahrenheit) of a cup of coffee, \(t\) minutes after forgetting it on a bench outside, is given by the function
\begin{equation*}
f(t) =
40 \, (0.5)^t + 50
\end{equation*}
Find \(f(1)\) and \(f'(1)\) and try to interpret your result in the context of this problem.
Answer.
\(f(1) = 70\text{.}\) This means that: 1 minute after forgetting a cup of coffee on the bench outside, the temperature of the cup of coffee is given by 70 degrees Fahrenheit.
\(f'(1) = 20\ln(0.5)\approx -13.86\text{.}\) This means that: 1 minute after forgetting a cup of coffee on the bench outside, the temperature of the cup of coffee is decreasing by 13.86 degrees Fahrenheit per minute.
Activity 10.62.
In this activity you will use our first derivative rules to study the slope of tangent lines.
(a)
The graph of \(y=x^3-9x^2-16x+1\) has a slope of 5 at two points. Find the coordinates of these points.
Answer.
The \(x-\)coordinates are \(x=-1, x=7\text{;}\) so, the coordinates are \((-1,7)\) and \((7,-209)\text{.}\)
(b)
Find the equations of the two lines tangent to the parabola \(y=(x-2)^2\) which pass through the origin. You will want to think about slope in two ways: as the derivative at \(x=a\) and the rise over the run in a linear function through the origin and the point \((a, f(a))\text{.}\) Use a graph to check your work and sketch the tangent lines on your graph.
Answer.
\(y = 0\) and \(y = -8x\)
Activity 10.63.
Find the values of the parameters \(a,b,c\) for the quadratic polynomial \(q(x)
= ax^2 +bx +c \) that best approximates the graph of \(f(x)=e^x\) at \(x=0\text{.}\) This means choosing \(a,b,c\) such that
- \(\displaystyle q(0) = f(0)\)
- \(\displaystyle q'(0) = f'(0)\)
- \(\displaystyle q''(0) = f''(0)\)
Hint: find the values of \(f(0),f'(0),f''(0)\text{.}\) The values of \(q(0),q'(0),q''(0)\) at zero will involve some parameters. You can solve for these parameters using the equations above.
Answer.
\(a = \dfrac{1}{2}\text{,}\) \(b = c = 1\)
Subsection 10.3.2 Videos
Subsection 10.3.3 Exercises
Exercises available at
https://tbil.org/preview/calculus/exercises/#/bank/DF3/
